Insulin drip calculation practice problems
Dosage calculation practice for nursing students: solve unlimited new problems below with instant checking, or work through the 15 problems with answers further down.
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Formula to use
Concentration (units/mL) = units in the bag ÷ mL in the bag
units/hr = units/kg/hr × weight (kg)
mL/hr = units/hr ÷ units/mL
Open the insulin drip (units/hr to ml/hr) calculator to check your own numbers step by step.
15 practice problems with answers
Solve each problem on paper first, then open the answer to compare every step.
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A regular insulin infusion of 100 units in 100 mL is running at 5 mL/hr. How many units per hour is the patient receiving?
Show the answer
- Concentration: 100 ÷ 100 = 1 unit/mL.
- 5 mL/hr × 1 unit/mL = 5 units/hr.
Answer: 5 units/hr
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A regular insulin infusion of 100 units in 100 mL is running at 7.5 mL/hr. How many units per hour is the patient receiving?
Show the answer
- Concentration: 100 ÷ 100 = 1 unit/mL.
- 7.5 mL/hr × 1 unit/mL = 7.5 units/hr.
Answer: 7.5 units/hr
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Order: regular insulin 0.1 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 103 kg. Available: 100 units of regular insulin in 100 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 100 units ÷ 100 mL = 1 unit/mL.
- 0.1 units/kg/hr × 103 kg = 10.3 units/hr.
- 10.3 ÷ 1 = 10.3 mL/hr, rounded to 10.3 mL/hr.
Answer: 10.3 mL/hr
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Order: regular insulin 0.1 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 102 kg. Available: 100 units of regular insulin in 100 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 100 units ÷ 100 mL = 1 unit/mL.
- 0.1 units/kg/hr × 102 kg = 10.2 units/hr.
- 10.2 ÷ 1 = 10.2 mL/hr, rounded to 10.2 mL/hr.
Answer: 10.2 mL/hr
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Order: regular insulin 0.1 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 55 kg. Available: 250 units of regular insulin in 250 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 250 units ÷ 250 mL = 1 unit/mL.
- 0.1 units/kg/hr × 55 kg = 5.5 units/hr.
- 5.5 ÷ 1 = 5.5 mL/hr, rounded to 5.5 mL/hr.
Answer: 5.5 mL/hr
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A regular insulin infusion of 100 units in 100 mL is running at 12 mL/hr. How many units per hour is the patient receiving?
Show the answer
- Concentration: 100 ÷ 100 = 1 unit/mL.
- 12 mL/hr × 1 unit/mL = 12 units/hr.
Answer: 12 units/hr
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Order: regular insulin 0.14 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 97 kg. Available: 100 units of regular insulin in 100 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 100 units ÷ 100 mL = 1 unit/mL.
- 0.14 units/kg/hr × 97 kg = 13.58 units/hr.
- 13.58 ÷ 1 = 13.58 mL/hr, rounded to 13.6 mL/hr.
Answer: 13.6 mL/hr
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Order: regular insulin 0.14 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 74 kg. Available: 100 units of regular insulin in 100 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 100 units ÷ 100 mL = 1 unit/mL.
- 0.14 units/kg/hr × 74 kg = 10.36 units/hr.
- 10.36 ÷ 1 = 10.36 mL/hr, rounded to 10.4 mL/hr.
Answer: 10.4 mL/hr
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Order: regular insulin 0.1 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 88 kg. Available: 250 units of regular insulin in 250 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 250 units ÷ 250 mL = 1 unit/mL.
- 0.1 units/kg/hr × 88 kg = 8.8 units/hr.
- 8.8 ÷ 1 = 8.8 mL/hr, rounded to 8.8 mL/hr.
Answer: 8.8 mL/hr
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A regular insulin infusion of 250 units in 250 mL is running at 6 mL/hr. How many units per hour is the patient receiving?
Show the answer
- Concentration: 250 ÷ 250 = 1 unit/mL.
- 6 mL/hr × 1 unit/mL = 6 units/hr.
Answer: 6 units/hr
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A regular insulin infusion of 250 units in 250 mL is running at 8 mL/hr. How many units per hour is the patient receiving?
Show the answer
- Concentration: 250 ÷ 250 = 1 unit/mL.
- 8 mL/hr × 1 unit/mL = 8 units/hr.
Answer: 8 units/hr
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Order: regular insulin 0.1 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 90 kg. Available: 250 units of regular insulin in 250 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 250 units ÷ 250 mL = 1 unit/mL.
- 0.1 units/kg/hr × 90 kg = 9 units/hr.
- 9 ÷ 1 = 9 mL/hr, rounded to 9 mL/hr.
Answer: 9 mL/hr
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Order: regular insulin 0.14 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 58 kg. Available: 100 units of regular insulin in 100 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 100 units ÷ 100 mL = 1 unit/mL.
- 0.14 units/kg/hr × 58 kg = 8.12 units/hr.
- 8.12 ÷ 1 = 8.12 mL/hr, rounded to 8.1 mL/hr.
Answer: 8.1 mL/hr
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Order: regular insulin 0.1 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 98 kg. Available: 100 units of regular insulin in 100 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 100 units ÷ 100 mL = 1 unit/mL.
- 0.1 units/kg/hr × 98 kg = 9.8 units/hr.
- 9.8 ÷ 1 = 9.8 mL/hr, rounded to 9.8 mL/hr.
Answer: 9.8 mL/hr
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Order: regular insulin 0.1 units/kg/hr IV for diabetic ketoacidosis. The patient weighs 53 kg. Available: 100 units of regular insulin in 100 mL 0.9% sodium chloride. At what rate in mL/hr will you set the pump?
Show the answer
- Concentration: 100 units ÷ 100 mL = 1 unit/mL.
- 0.1 units/kg/hr × 53 kg = 5.3 units/hr.
- 5.3 ÷ 1 = 5.3 mL/hr, rounded to 5.3 mL/hr.
Answer: 5.3 mL/hr